Least interval scheduling with cooldown
You are given a list of CPU tasks, each labeled by an uppercase letter, and a cooldown integer n. Each task takes one unit of time, and identical task labels must be separated by at least n units (the CPU may idle during the gap). Tasks may be run in any order. Return the minimum number of time units needed to finish all tasks. Here 0 <= n <= 100 and there is at least one task.
Implement
least_interval(tasks: list[str], n: int) → intExamples
in
[["A","A","A","B","B","B"],2]out8What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 20 min
solution.py
InputExpectedGot
[["A","A","A","B","B","B"],2]8not run yetsample