Stable partition by parity
Given an integer array a, return a new array with all even numbers first, then all odd numbers, where the relative order within the evens and within the odds is preserved (stable partition by parity). The array may be empty.
Implement
stable_partition_even_first(a: list[int]) → list[int]Examples
in
[[3,1,2,4]]out[2,4,3,1]What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 15 min
solution.py
InputExpectedGot
[[3,1,2,4]][2,4,3,1]not run yetsample