Task scheduling with cooldown
Given a list of tasks represented by uppercase letters and a non-negative integer n, where each task takes one unit of time, find the least time needed to finish all tasks. The same task must be separated by at least n units of idle (or other) time between two executions. Return the total number of time units (including any idle slots) required. The task list has 1 to 10^4 tasks and n is between 0 and 100.
Implement
least_interval(tasks: list[str], n: int) → intExamples
in
[["A","A","A","B","B","B"],2]out8What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 30 min
solution.py
InputExpectedGot
[["A","A","A","B","B","B"],2]8not run yetsample