Question
Implement a Unix-style permission check over a bitmask. Permissions are named bits given as a dict mapping name->bit value (a power of two). A user holds a granted integer mask. Given the granted mask, the dict of named bits, and a list of required permission names, return True only if EVERY required permission's bit is set in the granted mask. If a required name is not in the dict, treat the requirement as unsatisfiable and return False.
has_permissions(granted: int, bits: dict, required: list[str]) → bool[3,{"read":1,"admin":8,"write":2,"delete":4},["read","write"]]outtrueState your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.