Find conflicting employee emails
Two HR systems were merged, and the combined feed has rows "id,email". The same id may appear many times; identical repeats are fine, but an id listed with two or more DIFFERENT emails is a data conflict that must be escalated. Return the conflicting ids, sorted ascending. Example: ["e1,ava@co.io", "e2,raj@co.io", "e1,ava@old.io"] gives ["e1"].
Implement
conflicting_ids(rows: list[str]) → list[str]Examples
in
[["e1,ava@co.io","e2,raj@co.io","e1,ava@old.io"]]out["e1"]What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 14 min
solution.py
InputExpectedGot
[["e1,ava@co.io","e2,raj@co.io","e1,ava@old.io"]]["e1"]not run yetsample