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Code RoomDistinct words
EasyPrep Room Coding #568

Distinct words

CodingAlgorithms & data structuresEntry–Mid~10 min

A support dashboard estimates how varied a ticket's wording is. Given the ticket text — words separated by single spaces, possibly empty — return the number of distinct words when compared case-insensitively. For example, 'The printer THE PRINTER again' has 3 distinct words: 'the', 'printer', and 'again'.

Implement
count_unique_words(ticket: str) → int
Examples
in["The printer THE PRINTER again"]out3
What a strong answer looks like

State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.

0:00 of about 10 min
InputExpectedGot
["The printer THE PRINTER again"]3not run yetsample