Count vowel words
Given a sentence of words separated by single spaces (possibly the empty string), count how many words begin with a vowel — one of 'a', 'e', 'i', 'o', 'u' — comparing case-insensitively. For example, 'An apple every day' has 3 such words ('An', 'apple', 'every').
Implement
vowel_start_count(s: str) → intExamples
in
["An apple every day"]out3What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 10 min
solution.py
InputExpectedGot
["An apple every day"]3not run yetsample