Array is reversed copy
Given two integer arrays a and b, return True if b is exactly a reversed — same length, and b read left to right equals a read right to left. Compare using one pointer moving forward through a and one moving backward through b (or an index formula); do not materialize a reversed copy of either array. Example: a = [1, 2, 3], b = [3, 2, 1] returns True, while a = [1, 2], b = [1, 2] returns False.
Implement
is_reverse_of(a: list[int], b: list[int]) → boolExamples
in
[[1,2,3],[3,2,1]]outtrueWhat a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 10 min
solution.py
InputExpectedGot
[[1,2,3],[3,2,1]]truenot run yetsample