Code Room
CodingHard
Question
There are n piles of stones in a row; stones[i] is the count in pile i. In one move you merge two ADJACENT piles into one, paying a cost equal to the total stones in the two merged piles. Repeat until one pile remains. Return the minimum total cost. 1 <= n <= 200, 1 <= stones[i] <= 100.
Implement
merge_stones_cost(stones: list[int]) → intExamples
in
[[3,4,3]]out17What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Learn the concepts
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.
Run or narrate your approach, then ask the coach.