Count triplets less than target
Given an array nums and an integer target, count the number of index triples (i, j, k) with i < j < k such that nums[i] + nums[j] + nums[k] < target. Constraints: 0 <= len(nums) <= 3500, -100 <= nums[i] <= 100, -3*10^4 <= target <= 3*10^4. Aim for O(n^2).
Implement
three_sum_smaller(nums: list[int], target: int) → intExamples
in
[[-2,0,1,3],2]out2What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 26 min
solution.py
InputExpectedGot
[[-2,0,1,3],2]2not run yetsample