Code Room
CodingMedium
Question
There are n people standing in a circle numbered 1 to n. Starting the count at person 1, you count k people and eliminate the k-th; counting then resumes from the next survivor. Return the 1-indexed position of the last person remaining. Constraints: 1 <= n <= 1e6, 1 <= k <= 1e6. An O(n) solution is expected (no O(n*k) circular-list simulation).
Implement
josephus(n: int, k: int) → intExamples
in
[5,2]out3What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Learn the concepts
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.
Run or narrate your approach, then ask the coach.