Code Room
CodingMedium
Question
Given a non-negative integer n (0 <= n <= 2^63 - 1), return floor(sqrt(n)) as an integer, without using any library square-root or float-based math (no math.sqrt, no n**0.5). Floating point loses precision at large n, so use an integer method such as Newton's iteration.
Implement
int_sqrt(n: int) → intExamples
in
[8]out2What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Learn the concepts
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.
Run or narrate your approach, then ask the coach.