Code Room
CodingHard
Question
You have `stones` piles in a row. Repeatedly merge two ADJACENT piles into one; the cost of a merge is the sum of the two piles' sizes. Keep merging until a single pile remains. Return the minimum possible total merge cost. A single pile (or empty) costs 0.
Implement
min_merge_cost(stones: list[int]) → intExamples
in
[[4,3,3,4]]out28What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Learn the concepts
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.
Run or narrate your approach, then ask the coach.