Question
Given positive integer balloon values, you burst them one by one. Bursting balloon i earns left * value[i] * right coins, where left and right are the values of the adjacent surviving balloons (treat out-of-range neighbors as 1). After bursting, neighbors become adjacent. Return the maximum coins from bursting all balloons. The list has at least one balloon.
burst_balloons(nums: list[int]) → int[[3,1,5,8]]out167State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.