Question
Given a complete binary tree encoded as a dense level-order array (every level full except possibly the last, which is filled left to right with no gaps), return the number of nodes in O(log^2 n) time. Do not just return the array length: implement the height comparison: if a node's leftmost path height equals its rightmost path height, its subtree is perfect with 2^h - 1 nodes; otherwise recurse on both children. Return the node count.
count_complete_nodes(level: list[int]) → int[[1,2,3,4,5,6]]out6State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.