Question
Implement regular-expression matching for patterns where '.' matches any single character and '*' matches zero or more of the PRECEDING element. The match must cover the ENTIRE input string s (not a partial match). 0 <= len(s) <= 1000, 0 <= len(p) <= 1000; s is lowercase letters, p is lowercase letters plus '.' and '*' (a '*' always has a valid preceding element). Example: s='mississippi', p='mis*is*p*.' -> False.
is_regex_match(s: str, p: str) → bool["mississippi","mis*is*p*."]outfalseState your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.