Power of three
Return whether a given integer is a power of three.
Implement
is_power_of_three(n: int) → boolExamples
in
[27]outtrueWhat a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 15 min
solution.py
InputExpectedGot
[27]truenot run yetsample