Anagram groups
A word game bans usernames that are merely shuffles of one another, so the moderation team wants to know how many truly different names exist. Given a list of lowercase usernames, return the number of anagram groups: names that are anagrams of each other (same letters, same multiplicities) belong to one group. For example, ['listen', 'silent', 'enlist', 'google'] has 2 groups.
Implement
anagram_group_count(names: list[str]) → intExamples
in
[["listen","silent","enlist","google"]]out2What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 15 min
solution.py
InputExpectedGot
[["listen","silent","enlist","google"]]2not run yetsample