Counter operation sequences
A counter starts at 1. In one operation you either add 1 to it or double it. Count the distinct sequences of operations that turn 1 into exactly n (n >= 1). Two sequences are different if they differ anywhere, even when they pass through the same values — for example, reaching 2 by adding 1 and reaching 2 by doubling are two different sequences. Return the count; n = 1 gives 1 (the empty sequence).
Implement
count_counter_paths(n: int) → intExamples
in
[4]out4in
[6]out6What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 14 min
solution.py
InputExpectedGot
[4]4not run yetsample[6]6not run yetsample