Trailing zeros in factorial
Given a non-negative integer n (up to 10^9), return the number of trailing zeros in n! (n factorial). For example 5! = 120 has one trailing zero. You must not compute n! directly — it is astronomically large.
Implement
trailing_zeros_factorial(n: int) → intExamples
in
[5]out1What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
0:00 of about 18 min
solution.py
InputExpectedGot
[5]1not run yetsample