Code Room
CodingMedium
Question
Return the number of trailing zeros in n! (n factorial), where 0 <= n <= 1e9. For example 25! has 6 trailing zeros. You must not compute n! directly; derive the count from how many times 10 divides n!, which reduces to counting factors of 5.
Implement
factorial_trailing_zeros(n: int) → intExamples
in
[5]out1What a strong answer looks like
State your approach and its time/space complexity out loud before you optimize. Handle the edge cases (empty input, duplicates, overflow), and say why you chose this over the brute force. Green tests are the floor, not the grade.
Learn the concepts
Vibe coding: describe the solution in plain language (or narrate it) and the coach grades your approach. Generating runnable code from your description is coming next.
Run or narrate your approach, then ask the coach.